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A uniform rod AB of mass m is suspended ...

A uniform rod AB of mass m is suspended in equilibrium from two similar springs as shown. If spring 2 breaks, then the angular acceleration of the bar at that instant will be

A

`(2g)/l`

B

`(2g)/(3l)`

C

`(3g)/(l)`

D

`(g)/(3l)`

Text Solution

Verified by Experts

The correct Answer is:
C

m equilibrium
`2 kxsin 30^@ = mg`
kx = mg...(i)
When spring is snapped
Equation of rotation motion about COM.
`kx . sin 30^@ ""(1)/2= Ialpha`
`= (ml^2)/12 alpha implies alpha = (3g)/1`
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