In Young's double slit experiment, the `10^(th)` maximum of wavelength `lambda_(1)` is at a distance `y_(1)` from its central maximum and the `5^(th)` maximum of wavelength `lambda_(2)` is at a distance `y_(2)` from its central maximum. The ratio `y_(1)//y_(2)` will be

Options

A. `(2lamda_1)/(lamda_2)`
B. `(2lamda_2)/(lamda_1)`
C. `(lamda_1)/(2lamda_2)`
D. `(lamda_1)/(2lamda_1)`

Answer

A

Explanation

We know that position of `m^(th)` bright fringe is `y_m = (mlamdaD)/d`
Therefore, for wavelength `lamda_(1),y_1= (10lamda_1D)/d`
For wavelength `lamda_2,y_2=(5lamda_2D)/d`
`:. y_1/y_2=(2lamda_1)/lamda_2`