For a time-varying electromagnetic wave, the amplitude of the electric field is `2 V m^(-1)`, then the average energy density of the magnetic field is M (in `J m^(-3)`) . Find `M xx 10^(12)` =?

Explanation

To find the average energy density of the magnetic field (M) for a time-varying electromagnetic wave with an electric field amplitude (E₀) of 2 V/m, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the relationship between electric field and magnetic field**:
In an electromagnetic wave, the average energy density of the electric field (U_E) and the magnetic field (U_B) are related by the following equations:
\[
U_E = \frac{1}{2} \epsilon_0 E_0^2
...