In a sereis L-C-R circuit, `C = 10^(-11)` Farad, `L = 10^(-5)` Henry and R = 100 Ohm, when a constant D.C voltage E is applied to the circuit, the capacitor acquires a charge `10^(-9)C`. The D.C source is replaced by a sinusoidal voltage source in which the peak voltage `E_(0)` is equal to the constant D.C volatge E. At resonance the peak value of the charge acquired by the capacitor will be :

Answer

`8`

Explanation

As energy spread in capacitor `=1/2CV^(2)`
Nowthen AC is connected to the circuit energy speed `=1/2 LI^(2)`
By equating the energies,we get
`1/2CV^(2)=1/2LI^(2)impliesI=10A`
Now `V=IR=10xx100=1000V`
Therefore `Q=CV`
`=10^(-11)xx1000=10^(-8)C`