Home
Class 12
PHYSICS
A laser light of wavelength 660 nm is us...

A laser light of wavelength 660 nm is used to weld Retina detachment. If a laser pulse of width 60 ms and power 0.5 kW is used, the approximate number of photons in the pulse are (Take Planck's Constant, `h=6.62xx10^(-34)Js`)

A

`10^(22)`

B

`10^(19)`

C

`10^(20)`

D

`10^(18)`

Text Solution

Verified by Experts

The correct Answer is:
C

The energy of photon is given by
`E=(hc)/(lambda)`
Power P is given as, `P=(E)/(t)=(nhc)/(lambdat)`
From the above equation, the number of photons is `n (P lambda t)/(hc)`
`=0.5xx10^(3)xx(660xx10^(-9)xx60xx10^(-3))/(6.6xx10^(-34)xx3xx10^(8))`
Hence, number of photons in the pulse are `=100xx10^(18)=10^(20)`
Promotional Banner

Topper's Solved these Questions

  • NTA TPC JEE MAIN TEST 100

    NTA MOCK TESTS|Exercise PHYSICS (SUBJECTIVE NUMERICAL)|10 Videos
  • NTA NEET TEST 98

    NTA MOCK TESTS|Exercise PHYSICS|45 Videos
  • NTA TPC JEE MAIN TEST 101

    NTA MOCK TESTS|Exercise PHYSICS |30 Videos

Similar Questions

Explore conceptually related problems

A laser emits a pulse of light with energy 5.0 xx 10^(3)J . Determine the number of photons in the pulse if the wavelength of light is 480 nm.

What is the number of significant figures in Avogadro's number (6.0 xx 10^(23)) and Planck's constant (6.62 xx 10^(-34) J s) .

A ball of mass 0.12 kg is moving with a speed 20 m//s . Calculate the de Broglie wavelength. (planck constant h= 6.62xx10^(-34)J.s )

A ruby laser produces radiations of wavelength, 662.6nm in pulse whose duration are 10^(-9)s . If the laser produces 0.39 J of energy per pulse, how many protons are produced in each pulse?

A laser beam of output power 'P' consists only of wavelength lambda . If Planck's constant is h and the speed of light is c , then the number of photons emitted per second is

A monochromatic source emitting light of wavelength, 600nm, has a power output of 66W. Caculate the number of photons emitted by this source in 2minuts. Use h=6.6xx10(-34)Js .

One milliwatt of light of wavelength 4560 A is incident on a cesium surface. Calculate the photoelectric current liberated assuming a quantum efficiency of 0.5 %. Given Planck's constant h=6.62xx10^(-34)J-s and velocity of light c=3xx10^(8)ms^(-1) .

A radiostation broadcasts at frequency of 100 MHz. If the radiating power of the transmitter is 66.6 KW, then the number of photons radiated per second is [ Take h=6.66xx10^(-34)Js ]

The de - Broglie wavelength of a ball of mass 120 g moving at a speed of "20 m s"^(-1) is (Planck's constant h=6.6xx10^(-34)Js )