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Find the magnitude of the magnetic field...

Find the magnitude of the magnetic field at the center of an equilateral triangular loop of side length 1m which is carrying a current of 10A. ( Take `mu_(0) = 4pi xx 10^(-7) NA^(-2))`

A

`18 muT`

B

`1 muT`

C

`9 muT`

D

`3 muT`

Text Solution

Verified by Experts

The correct Answer is:
A
Magnetic field due to wire BC is
`rArr B= (mu_(0))/(4pi) (i)/(l)xx2 sqrt(3) [ (sqrt(3))/(2)+(sqrt(3))/(2)]o+`
Net magnetic field at centre =3B
`=(mu_(0))/(4pi) (i)/(l) 6(1) 3= 10^(-7)xx(10)/(1) xx18=18 xx10^(-6)T`
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