Home
Class 12
PHYSICS
Find the resultant amplitude of the foll...

Find the resultant amplitude of the following simple harmonic equations `:`
`x_(1) = 5sin omega t`
`x_(2) = 5 sin (omega t + 53^(@))`
`x_(3) = - 10 cos omega t `

A

5

B

10

C

15

D

20

Text Solution

Verified by Experts

The correct Answer is:
B
`x_(1)=5 sin omegat`
`x_(2)=5 sin (omegat+53^(@))`
`x_(3)=-10 cos omegat`
we can write
`x_(3)=10 sin (omegat-90^(@))` Finding the resultant amplitude by vector notation.

Resultant Amplitude
`|R|= sqrt(8^(2)+6^(2))=10`
Promotional Banner

Topper's Solved these Questions

  • NTA TPC JEE MAIN TEST 100

    NTA MOCK TESTS|Exercise PHYSICS (SUBJECTIVE NUMERICAL)|10 Videos

  • NTA NEET TEST 98

    NTA MOCK TESTS|Exercise PHYSICS|45 Videos

  • NTA TPC JEE MAIN TEST 101

    NTA MOCK TESTS|Exercise PHYSICS |30 Videos

Similar Questions

Explore conceptually related problems

The resultant amplitude due to superposition of three simple harmonic motions x_(1) = 3sin omega t , x_(2) = 5sin (omega t + 37^(@)) and x_(3) = - 15cos omega t is

x_(1) = 3 sin omega t x_(2) = 5 sin (omega t + 53^(@)) x_(3) = - 10 cos omega t Find amplitude of resultant SHM.

The resultant amplitude due to super position of x_(1)=sin omegat, x_(2)=5 sin (omega t +37^(@)) and x_(3)=-15 cos omega t is :

If i_(1) = 3 sin omega t and i_(2) =6 cos omega t , then i_(3) is

If i_(1)=3 sin omega t and (i_2) = 4 cos omega t, then (i_3) is

The ratio of amplitudes of following SHM is x_(1) = A sin omega t and x_(2) = A sin omega t + A cos omega t

Find the displacement equation of the simple harmonic motion obtained by combining the motion. x_(1) = 2sin omega t , x_(2) = 4sin (omega t + (pi)/(6)) and x_(3) = 6sin (omega t + (pi)/(3))

Find the amplitude of the harmonic motion obtained by combining the motions x_(1) = (2.0 cm) sin omega t and x_(2) = (2.0 cm) sin (omega t + pi//3) .

Find the resultant amplitude and the phase difference between the resultant wave and the first wave , in the event the following waves interfere at a point , y_(1) = ( 3 cm) sin omega t , y_(2) = ( 4 cm) sin (omega t + (pi)/( 2)), y_(3) = ( 5 cm ) sin ( omega t + pi)