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A man throws a ball of mass m from a mov...

A man throws a ball of mass m from a moving plank (A). The ball has a horizontal component of velocity `u=3sqrt(34)ms^(-1)` with respect to ground towards another man standing on stationary plank (B), as shown in the figure. The combined mass of plank A with man is 2m each. The x-y plane represents the horizontal plane which is frictionless. If initially, plank A was moving with speed `uhati` with respect to ground, then the relative velocity of plank B `("in m s"^(-1))` with respect to plank A (after the man on plank B catches the ball) minus `10ms^(-1)` is

Text Solution

Verified by Experts

The correct Answer is:
7
By conservation of momentum,
`3m u hati=m( u cos 37^(@) hati+u sin 37^(@) hatj)+ 2m vecC_(A)`
`=vecV_(A)=(11 u)/(10) hati-(3u)/(10) hatj`
Similarly `=vecV_(B)= (4u)/(15) hati+(3u)/(10) hatj`
`:. |V_(BA)|=17 ms^(-1)`
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