A uniform rope of mass 6 kg and length 6 m hangs vertically from a rigid support. A block of mass 2 kg is attached to the free end of the rope. A transverse pulse of wavelength 0.075 m is produced at the lower end of the rope. The wavelength of the pulse when it reaches the top of the rope is K cm where K is

Answer

15

Explanation

`T_(1) = 2xx 10 = 20 N`
`T_(2) = (2+ 6) 10 = 80N `
`(V_(2))/(V_(1)) = sqrt((80)/(20))=2 `
Frequency remains unchanged
So `(lambda_(2))/(lambda_(1)) = 2 `
`lambda_(2) = 2 xx 0.075 `
`= 0.15 m`
`K = 15 `cm