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According to Bohr's theory of hydrogen a...

According to Bohr's theory of hydrogen atom , the product of the binding energy of the electron in the nth orbit and its radius in the nth orbit

A

is proportional to `n^(2-)`

B

is inversely proportional to `n^(3)`

C

has a constant value of `10.2eVÅ`

D

has constant value `7.2eVÅ`

Text Solution

Verified by Experts

The correct Answer is:
D

Binding energy of electron is given by
`E_(n)prop1/(n^(2))`, where n represents number of Bohr.s orbit.
And radius of Bohr.s orbit is given by
`r_(n)propn^(2)`
`:.E_(n)r_(n)` is independent of n
Hence
`E_(1)r_(1)=(13.6eV)(0.53Å)=7.2eVÅ`
= constant
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