Two coils have a mutual inductance `0.005 H`. The current changes in the first coil according to equation `I=I_(0)sin omegat`, where `I_(0)=10A` and `omega=100pi`radian//sec`. The maximum value of e.m.f. in the second coil is

Options

A. `2piV`
B. `5piV`
C. `piV`
D. `4piV`

Answer

B

Explanation

According to Faraday.s law of induction
`e=M(di)/(dt)=M(d(I_(0)sin (omega t)))/(dt)`
On differentiating we get
`=0.005xxI_(0)omega cos omega t`
on comparing with equation
`e=e_("max")cos(omegat)`
We get maximum value of
`:.e_("max")=0.005xx10xx100pi`
`=5piV`
`[ :, cos omega t=1]`