For the projectile motion, the speed of the projectile when the angle between the initial velocity vector and the velocity vector at that instant becomes `90^(@)` will be ……m/s

Answer

`5.77`

Explanation

As we know that horizontal
component always remains constant.
`:. cos 60^(2)=v cos 30^(@)`
`impliesv=(u(1//2))/(sqrt(3)//2)=u/(sqrt(3))`
`=10//sqrt(3)=5.77m//s`