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Calculate x in the equation : (velocity)...

Calculate x in the equation : `(velocity)^x = (pressire diff.)^(3//2)xx(density)^(-3//2)`

Text Solution

Verified by Experts

The correct Answer is:
`3`

`("Velocity")^(x)=P^(3//2)xrho^(-3//2)=(p/(rho))^(2)`
`=[(ML^(-1)T^(-2)]^(3/2)/([ML^(-3)])]`
`=[L^(2)T^(-2)]^(3//2)`
`=[L^(3)T^(-3)]`
`=[L^(1)T^(-1)]^(3)`
But `[L^(1)T^(-1)]` is the dimension of velcoity.
`impliesx=3`
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