sintheta=(a^2-b^2)/(a^2+b^2) हो, तब cost...

`sintheta=(a^2-b^2)/(a^2+b^2)` हो, तब `costheta` का मान होगा-
A)`(2ab)/(a^2-b^2)`
B)`(a^2+b^2)/(a^2-b^2)`
C)`(2ab)/(a^2+b^2)`
D)`(2a^2b^2)/(a^2+b^2)`

A

`(2ab)/(a^2-b^2)`

B

`(a^2+b^2)/(a^2-b^2)`

C

`(2ab)/(a^2+b^2)`

D

`(2a^2b^2)/(a^2+b^2)`

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The correct Answer is:

C

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