a). `√1183/(2023)` b). `√72 * √98`

60.5 72 84.5 98 112.5 ?

sqrt72 xx sqrt98= ?

Evaluate: (sqrt (1183))/(sqrt (2023))

Write the following in Roman numerals: (i) 49 (ii) 69 (iii) 72 (iv) 89 (v) 98 (vi) 92

Let omega ne 1 be cube root of unity. Suppose (1 + omega)^(2023) = A + B omega where A, B in R, then |A + Bi|^(2) is equal to ______________.

If sqrt(2) = 1.414 then find the value of sqrt(8) + sqrt(50) + sqrt(72) + sqrt(98)

The least number,which when divided by 48,60,72,108 and 140 leaves 38,50,62,98 and 130 as remainders respectively is (a) 111115 (b) 15110 (c) 15120 (d) 15210

The value of (.98)^(3)+(.02)^(3)+3xx.98xx.02-1 is (a) 0 (b) 1(c)1.09(d)1.98

The predecessor of -99 is -98 (b) -100 (c) 98 (d) 100