`icos(pi/6)+sin(pi/6)=?`

sin(pi+pi/6)=

sin(pi/3-x)cos(pi/6+x)+cos(pi/3-x)sin(pi/6+x)=1

sin((13pi)/3)sin((8pi)/3)+cos((2pi)/3)sin((5pi)/6)=1/2

Prove that : cos(A-B) = cos((pi)/(6)+A).cos((pi)/(6)+B)+sin((pi)/(6)+A).sin((pi)/(6)+B).

The number of solutions of the equation cos^(2)(x+(pi)/(6))+cos^(2)x-2cos(x+(pi)/(6))*cos(pi)/(6)=sin^(2)(pi)/(6) in interval ((-pi)/(2),(pi)/(2)) is

If z=cos((pi)/(4))+i sin((pi)/(6)), then

What is the values of tan ((5pi)/(6))sin((7pi)/(6)) ?

What is [((sin(pi))/(6)+i(1-cos((pi)/(6))))/((sin(pi))/(6)+-(1-cos((pi)/(6))))]^(3) where i=sqrt(-1) equal to

int(sin(2x))/(sin(x+(pi)/(6))sin(x-(pi)/(6)))dx

Prove that (a) sin^(2)(pi/6) + cos^(2)( pi/3) - tan^(2)(pi/4) = -1/2 (b) sin((8pi)/3) cos((23pi)/6) + cos((13pi)/3) sin((35pi)/6) = 1/2