Two elements `A` and `B` form compounds having formula `AB_(2)` and `AB_(4)`.When dissolved in `20g` of benzene `(C_(6)H_(6))`,`1g` of `AB_(2)` lowers the freezing point by `2.3K` whereas `1.0g` of `AB_(4)` lowers it by `1.3K`.The molar depression constant for benzene is `5.1Kkgmol`.Calculate atomic masses of `A` and `B`.

Two elements A and B form compounds having molecular formula AB_(2) and AB_(4) . When dissolved in 20 g of benzene, 1 g of AB_(2) lowers the freezing point by 2.3 K , whereas 1.0 g of AB_(4) lowers it by 1.3 K . The molar depression constant for benzene is 5.1 K kg mol^(-1) . Calculate the atomic mass of A and B .

The elements X and Y form compound having molecular formula XY_(2) and XY_(4) (both are non - electrolysis), when dissolved in 20 g benzene, 1 g XY_(2) lowers the freezing point by 2.3^(@)c whereas 1 g of XY_(4) lowers the freezing point by 1.3^(C) . Molal depression constant for benzene is 5.1. Thus atomic masses of X and Y respectively are

1.0 g of non-electrolyte solute dissolved in 50.0 g of benzene lowered the freezing point of benzene by 0.40 K . The freezing point depression constant of benzene is 5.12 kg mol^(-1) . Find the molecular mass of the solute.

0.48 g of a substane was dissolved in 10.6g C_(6)H_(6) . The freezing point of benzene was lowered by 1.8^(@)C . Calculate m.w.t. of the substance. Molecular depression constant for benzene is 50 K"mol"^(-1) 100 g .

2g of benzoic acid (C_(6)H_(5)COOH) dissolved in 25g of benzene shows a depression in freezing point equal to 1.62K .Molal depression constant for benzene is 4.9Kkgmol^(-1) .What is the percentage association of acid if it forms dimer in solution?

2g of benzoic acid (C_(6)H_(5)COOH) dissolved in 25g of benzene shows a depression in freezing point equal to 1.62K .Molal depression constant for benzene is 4.9Kkgmol^(-1) .What is the percentage association of acid if it forms dimer in solution?

The freezing point of a solution of 2.40 g of biphenyl ( C_(12)H_(10) ) in 75.0 g of benzene ( C_(6)H_(6) ) is 4.40^(@)C . The normal freezing point of benzene is 5.50^(@)C . What is the molal freezing point constant (@C//m) for benzene ?

Calculatate the mass of compound (molar mass = 256 g mol^(-1) be the dissolved in 75 g of benzene to lower its freezing point by 0 .48 k(k_(f) = 5. 12 k kg mol ^(-1) .

Two grams of benzoic acid (C_(6)H_(5)COOH) dissolved in 25.0 g of benzene shows a depression in freezing point equal to 1.62 K . Molal depression constant for benzene is 4.9 K kg^(-1)"mol^-1 . What is the percentage association of acid if it forms dimer in solution?

Two grams of benzoic acid (C_(6)H_(5)COOH) dissolved in 25.0 g of benzene shows a depression in freezing point equal to 1.62 K . Molal depression constant for benzene is 4.9 K kg^(-1)"mol^-1 . What is the percentage association of acid if it forms dimer in solution?