Home
Class 12
CHEMISTRY
A solid is formed by A^(3+) cations &B^(...

A solid is formed by `A^(3+)` cations &`B^(2-)` anions in which `B^(2-)` - form F.C.C structure and `A^(3+)` ions occupy m fraction of octahedral voids.Find the value of `m` as `(x)/(y)`,where `x&y` are lowest integers.Fill your answer as `10(x+y)`

Promotional Banner

Similar Questions

Explore conceptually related problems

Find the minimum value of (a x+b y), where x y=c^2dot

Find the minimum value of a x+b y , where x y=c^2 and a ,\ b ,\ c are positive.

In an ionic solid, B^(x-) ions constitute a ccp lattice, if A^(y+) ions occupy 25%, of the tetrahedral voids, the possible ions in the solid are

If the anions (X) form hexagonal closed packing and cations (Y) occupy only 3/8th of octahedral voids in it, then the general formula of the compound is

If the anion (A) form hexagonal closet packing and cation (C ) occupy only 2/3 octahedral voids in it, then the general formula of the comound is:

A solid is formed and it has three types of atoms X, Y, Z. X forms an FCC lattice with Y atoms occupying one-fourth of tetrahedral voids and Z atoms occupying half of the octahedral voids. The formula of the solid is

Find the value of m, if x = 2, y = 1 is a solution of the equation 2x + 3y = m.

A solid is formed and it has three types of atoms X, Y and Z, X forms a fcc lattice with Y atoms occupying all tetrahedral voids and Z atoms occupying half of octahedral voids. The formula of solid is :-

M^(+)X^(–) has fcc structure with octahedral voids. Anion has radius of 300 pm. The ideal radius of cation will be :

In a solid ,oxide (O^(2-)) ions are arranged in ccp, cations (A^(3+)) occupy one -fourth of tetrahedral void and cations (B^(3+)) occupy half of the octahedral voids . What is the formula of the compound?