For the given reaction at equilibrium moles of `Cl_(2(g))` is equal to the moles of `Cl_((g))` and equilibrium pressure is `1atm`.if `K_(p)` of this reaction is `x times10^(-1)`.Find `x`

At 227^(@)C the reaction 2SO_(2(g))+O_(2(g))hArr2SO_(3(g)) is carried out in a 10 litre vessel till equilibrium is reached. At equilibrium moles of SO_(2) equal to moles of SO_(3) . Find moles of O_(2) at equilibrium (Given : K_(C)=10^(2) mole lit^(-1) )

(K_p/K_c) for the given equilibrium is [PCl_5 (g) hArrPCl_3(g) + Cl_2 (g)]

n mole of PCl_(3) and n mole of Cl_(2) are allowed to react at constant temperature T to have a total equilibrium pressure P , as : PCl_(3)(g)+Cl_(2)(g) hArr PCl_(5)(g) If y mole of PCl_(5) are formed at equilibrium , find K_(p) for the given reaction .

At 600^(@)C,K_(P) for the following reaction is 1 atm. X(g) rarr Y(g) + Z(g) At equilibrium, 50% of X (g) is dissociated. The total pressure of the equilibrium system is p atm. What is the partial pressure (in atm) of gases at equilibrium ?

For the reaction is equilibrium : 2NOBr_((g))hArr2NO_((g))+Br_(2(g)) If P_(Br_(2)) is (P)/(9) at equilibrium and P is total pressure, prove that (K_(p))/(P) is equal to (1)/(81) .

For the reaction C(s)+CO_(2)(g) hArr 2CO(g) , the partial pressure of CO_(2) and CO is 5.0atm amd 10 atm, respectively, at equilibrium. The K_(p) of the reaction is

For the reaction C(s)+CO_(2)(g) hArr 2CO(g) , the partial pressure of CO_(2) and CO is 4.0atm amd 8.0 atm, respectively, at equilibrium. The K_(p) of the reaction is

In 500 ml capacity vessel CO and Cl_(2) are mixed to form COCl_(2) . At equilibrium, it contains 0.2 moles of COCl_(2) and 0.1 mole of each of CO and Cl_(2) , The equilibrium constant K_(C) for the reaction CO(g)+Cl(g)hArrCOCl_(2)(g) is

For the reactions, CO(g) +Cl_2( g) hArr COCl_2(g), " the " (K_P)/(K_c) is equal to

For the reaction : 2NO(g) + Cl_(2) (g) hArr 2NOCl (g), NO and Cl_(2) are initially taken in mole ratio 2 : 1 . The total pressure at equilibrium is found to be 1 atm . If mole of NOCl are one fourth of that of Cl_(2) at equilibrium, K_(p) for the reaction is: