280mL of sulphur vapour `Sx` at 1atm,273K weighs 1.6gm.Determine the molecular formula of sulphur vapour?

"280mL" of sulphur vapour "(S_(x))" at "1atm,273K" weighs "1.6gm".Determine the molecular formula of sulphur vapour? "S" "S_(4)" "S_(6)" "S_(8)"

448 mL of a hydrocarbon, having C = 87.8%, H = 12.19%, weigh 1.64 g at S.T.P Determine the molecular formula of the compound.

When 3.2 g S is vaporized at 450^(@)C and 723 mm pressure, the vapours occupy a volume of 780 mL What is the molecular formula of S vapours ?

A hydrocarbon contains 10.5 g of carbon per gram of hydrogen. 1 L of vapour of the hydrocarbon at 127^(@)C and 1 atm pressure weighs 2.8 g . Find the molecular formula of the hydrocarbon.

At 48^(@)C , the vapour pressure of pure CS_(2) is 850torr . A solution of 2.0 g of sulphur in 100g of CS_(2) has a vapour pressure 844.9 torr. Determine the atomicity of sulphur molecule :

A hydrocarbon contains 10.5 g of carbon per gram of hydrogen. 1 litre of the vapour of the hydrocarbon at 127°C and 1 atmosphere pressure weighs 2.8g. Find the molecular formula of the hydrocarbon.

0.246 gm of an organic compound gave 0.198 gm of carbon dioxide and 0.1014 gm of water on complete combustion. 0.37 gm of the compound gave 0.638 gm of silver bromide. What is the molecular formula of the compound if its vapour density is 54.4?

A sample of phosphorus that weighs 12.4g exerts a pressure 8 atm in a 0.821 litre closed vesel at 527^@ C . The molecular formula of the phosphorus vapour is :

A sample of phosphorus that weighs 12.4g exerts a pressure 8 atm in a 0.821 litre closed vesel at 527^@ C . The molecular formula of the phosphorus vapour is :

A saturated hydrocarbon having molecular formula C_(n)H_(2n+2) diffuses through a porous membrane twice as fast as Sulphur dioxide. Determine the molecular mass of hydrocarbon and name it.