An organic compound on analysis gave the following data `C=53.33%,H=15.56%,N= 31.11%`. Its empirical formula is

An organic compound on analysis gave the following data: (i). 0.25 gm of the compound on complete combustion gave 0.37 gm of CO_2 and 0.2 gm of water. (ii). 0.25 gm of the compound on analysis by Dumas method gave 32 ml of nitrogen gas at STP. Calculate the percentages of C,H,N and O in the organic compounds.

An organic compound containing C,H and N gave the following analysis C=40 %,H=13.33 %,N=46.67 % What would be its empirical formula ?

An inorganic substance on analysis gave the following results Na = 29.1%, S = .40.5% and O = 30.4%. Calculate its empirical formula.

An organic compound containes C=74.0%, H=8.65% and N=17.3% . Its empirical formul ais

A compound on analysis was found to contain C = 34.6 %, H = 3.85 % and O = 61.55% .Calculate its empirical formula.

A compound on analysis gave the follwing result C=54.54%, H=9.09% and vapour density of compound = 88.Determine the molecular formula of the compound.

An organic diabasic acid (A) gave the following on analysis : C = 57.8 %, H = 3.6 % . Its silver salt contained 56.8 % Ag . On heating (A) gives a product (B) which on heating with NH_3 gives ( C) (C_8 H_5 O_2 N) . Compound ( C) forms potassium salt with alc. KOH and is converted into o-aminobenzoic acid with NaClO . Assign structures to (A), (B), and ( C) .

An organic compound containing C,H and N have the percentage 40,13.33 and 46.67 respectively. Its empirical formula may be :

An organic compound is found to contain C - 40%. 0 = 53.34% and H = 6.66%. Its empirical formula is

An inorganic compound on analysis was found to have following composition : Mg = 9.76%, S = 13.01%, O = 26.01%, H_2O = 51.22% Calculate the empirical formula of the compound.