`31g` of an unknown molecular material is dissolved in `500g` of water.The resulting solution freezes at `271.14K`.Calculate the molar mass of the material [Given `K_(f)=1.86Kkgmol^(-1)` and `T_(f)^(0)` of water =273]`

(a) Define the following terms : (i) Mole fraction (ii) Ideal solution (b) 15.0 g of an unknown molecular material is dissolved in 450g of water . The resulting solution freezes at -0.34^(@)C . What is the molar mass of the material ? (K_(f) for water = 1.86 K kg mol^(-1))

15.0 g of an unknown molecular material was dissolved in 450 g of water. The reusulting solution was found to freeze at -0.34 .^(@)C . What is the the molar mass of this material. ( K_(f) for water = 1.86 K kg mol^(-1) )

15.0 g of an unknown molecular material was dissolved in 450 g of water. The resulting solution was found to freeze at -0.34 ^(@)C . What is the the molar mass of this material. ( K_(f) for water = 1.86 K kg mol^(-1) )

When 45gm solution is dissolved in 600gm water freezing point lower by 2.2K ,calcuate molar mass of solute (K_(f)=1.86 "kg mol"^(-1))

6 g of a substance is dissolved in 100 g of water depresses the freezing point by 0.93^(@)C . The molecular mass of the substance will be: ( K_(f) for water = 1.86^(@)C /molal)

5 g of a substance when dissolved in 50 g water lowers the freezing by 1.2^(@)C . Calculate molecular wt. of the substance if molal depression constant of water is 1.86 K kg mol^-1 .

1.355 g of a substance dissolved in 55 g of CH_(3)COOH produced a depression in the freezing point of 0.618^(@)C . Calculate the molecular weight of the substance (K_(f)=3.85)

What is the g-molecular mass of nonionizing solid if 10 g of this solid dissolved in 100 g of water, forms a solution which froze at -1.22^(@) C ? (K_(f)=1.86 K kg mol^(-1))

When 45 g of an unknown compound was dissolved in 500 g of water, the solution has freezing point of -0.93^(@)C (i) What is the molecular weight of compound ? (K_(f)=1.86) (ii) If empirical formula is CH_(2)O , what is the molecular formula of compound ?

0.1 mole of sugar is dissolved in 250 g of water. The freezing point of the solution is [K_(f) "for" H_(2)O = 1.86^(@)C "molal"^(-1)]