Solve, integrate `∫ (dθ)/(sin^2θ * cos^2θ)`

If 2cos^(2)θ + 3sinθ = 3 , where 0^circ lt θ lt 90^circ , then what is the value of sin^(2)2θ + cos^2 (θ) + tan^(2)2θ + cos^(2) 2θ = ? यदि 2cos^(2)θ + 3sinθ = 3 , जहा 0^circ lt θ lt 90^circ तो sin^(2)2θ + cos^(2(θ + tan^(2)2θ + cos^(2)2θ का मान बराबर है :

Trigonometric identities with proOF || Multiplicative inverse || Sin2θ + cos2θ =1 || sec2θ -tan2θ =1 || cosec2θ -cot2θ =1 || Exemplar questions discussion

If 5sin θ – 4cos θ = 0, 0^circ lt θ lt 90^circ , then the value of (5sinθ− 2cosθ)/ (5 sin θ + 3cosθ) is: यदि 5sin θ – 4cos θ = 0, 0^circ lt θ lt 90^circ है, तो (5sinθ− 2cosθ)/ (5 sin θ + 3cosθ) का मान है:

Sec^2θ + cosec^2θ = sec^2θ * cosec^2θ

Solve the following integration int (cos x - sin x)/(cos x + sin x)*(2+2 sin 2x)dx

Solve the following integration int(sin 2x+sin 5x-sin 3x)/(cos x+1-2 sin^(2)2x)dx

Solve the following integration int (sin x+cos x)/(sqrt(1+sin 2x))*dx , here (sin x + cos x) gt 0

If θ lies in the first quadrant and cos^(2) θ – sin^(2) θ = 1/2 , then the value of tan^(2)2θ + sin^(2)3θ is: यदि θ प्रथम चतुथथांश में है और cos^(2) θ – sin^(2) θ = 1/2 , तो tan^(2)2θ + sin^(2)3θ का मान है:

(sinθ - 2sin^3θ)/(2cos^3θ - cosθ) = tanθ

The value of (sec^(2)θ /cosec^(2)θ) + (cosec^(2)θ /sec^(2)θ )-(sec^(2)θ + cosec^(2)θ) is : (sec^(2)θ /cosec^(2)θ) + (cosec^(2)θ /sec^(2)θ )-(sec^(2)θ + cosec^(2)θ) का मान बराबर है :