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A man having the genotype EEFfGgHH can p...

A man having the genotype EEFfGgHH can produce P number of genetically different sperms, and a woman of genotype liLLMmNn can generate Q number of genetically different eggs. Determine the values P and Q.
a. P = 4, Q = 4
b. P = 4,Q = 8
c. P = 8, Q = 4
d. P = 8,Q = 8

A

P = 4, Q = 4

B

P = 4,Q = 8

C

P = 8, Q = 4

D

P = 8,Q = 8

Text Solution

Verified by Experts

The correct Answer is:
B
Types of gametes `= 2^(n)`, where n is number of heterozygous loci. Thus, man will produe `2^(2) = 4` types of gametes and woman will produce `2^(3) = 8` types of gametes.
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