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At a particular locus, frequency of alle...

At a particular locus, frequency of allete A is 0.6 and that of allele a is 0.4. what would be the frequency of heterozygotes in a random mating population at equilibrium?

A

0.36

B

0.16

C

0.24

D

0.48

Text Solution

Verified by Experts

The correct Answer is:
D
In a stable population, for a gene with two alleles, 'A' (dominant) and 'a' (recessive), if the frequency of 'A' is P and the frequency of 'a' is q, then the frequencies of the three possible genotypes (AA,Aa and aa) can be expressed by the Hardy-Weinberg equation:
`p^(2)+2pq+q^(2)=1`
where `p^(2)=` Freqeuncy of A A (homozygous dominant)
Inviduals
`q^(2)=` Frequency of Aa (heterozygous) individuals.
so, p=0.6 and q=0.4 (given)
`therefore 2pq` (frequency of heterozygote) `=2xx0.6xx0.4=0.48`.
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