In 2005, for each of the 14 million people present in a country, `0.028` were born and `0.008` died during the year. Using exponential equation, the number of people present in 2015 is predicted as
In 2005, for each of the 14 million people present in a country, `0.028` were born and `0.008` died during the year. Using exponential equation, the number of people present in 2015 is predicted as
A
25 millions
B
17 millions
C
20 millions
D
18 millions
Text Solution
Verified by Experts
The correct Answer is:
B
Exponential equation gives populatin growth rate as `(dN)/(dt) = rN`
Here,r = intrinsic rate of natural increase N = size of original population `(dN)/(dt)` = Increase in populatin size per unit time (1 year in this case)
r is the difference between birth and death rate. `r = 0.028-0.008=0.02`
`therefore(dN)/(dt)=0.02xx14" million"= 0.28 " million"` Over 10 years (2005 - 2015), this number will become = 2.8 million.
Expected population in 2015 = `(14+2.8)` million
= 17 million (approx.)
Here,r = intrinsic rate of natural increase N = size of original population `(dN)/(dt)` = Increase in populatin size per unit time (1 year in this case)
r is the difference between birth and death rate. `r = 0.028-0.008=0.02`
`therefore(dN)/(dt)=0.02xx14" million"= 0.28 " million"` Over 10 years (2005 - 2015), this number will become = 2.8 million.
Expected population in 2015 = `(14+2.8)` million
= 17 million (approx.)
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