`(8)^3 xx (-6)^3 xx (3)^3`

Simplify: (6/7)^3 xx (7/6)^2 xx ((-6)/8)^3

(-8)^3xx(-9)^3-:6^5

Write each of the following in power notation: ( i ) frac(5)(7)xxfrac(5)(7)xxfrac(5)(7)xxfrac(5)(7) ( ii ) (frac(-4)(3)) xx (frac(-4)(3)) xx (frac(-4)(3)) xx (frac(-4)(3)) xx (frac(-4)(3)) ( iii ) (frac(-1)(6)) xx (frac(-1)(6)) xx (frac(-1)(6)) ( iv ) (-8) xx (-8) xx (-8) xx (-8) xx (-8)

Find the products : (i) (-2) xx 3 xx (-4) " " (ii) 2 xx (-5) xx (-6) " " (iii) (-8) xx 3 xx 5 (iv) 8 xx 7 xx (-10) " " (v) (-3) xx (-7) xx (-6)

(3^8 xx b^6)/(9^3 xx b^4)

If root3((3^(6) xx 4^(3) xx 2^(6))/(8^(9) xx2^(3)))=(3/8)^(k) ,then k = _______ .

Fill in the blanks i (-6)xx(........) = 6 ii (-18)xx(.......) = (-18) iii (-8) xx (-9) = (-9) xx (...) iv 7 xx (-3) = (-3) xx (…) v {(-5)x3}x(-6) = (...)xx{3xx(-6)} vi (-5)x(...)=0