The refractive index of the material of a prism is 1.5 and its refracting angle is 6º. Find the deviation produced by the prism for a small angle of incidence.

The refractive index of the material of a prism of refracting angle 45^@ is 1.6 for a certain monochromatic ray. What will be the minimum angle of incidence of this ray on the prism so that no TIR takes place as the ray comes out of the prism.

The refractive index of a prism is 2. this prism can have a maximum refracting angle of

The refractive index of the material of prism sqrt3, then the angle of minimum deviation of prism is

The refractive index of a prism for a monochromatic wave is sqrt(2) and its refracting angle is 60^(@) for minimum deviation, the angle of indidence will be

The refractive index of a prism for a monochromatic wave is sqrt(2) and its refracting angle is 60^(@) for minimum deviation, the angle of indidence will be

The refractive index of the material of a prism is sqrt(2) and the angle of the prism is 30^(@) . One of the two refracting surfaces of the prism is made a mirror inwards, by silver coating. A beam of monochromatic light entering the prism from the other face will retrace its path (after reflection from the silvered surface) if its angle of incidence on the prism is

A prism has refractive index sqrt((3)/(2)) and refractive angle 90^@ . Find the minimum deviation produced by prism

If the refracting angle of a prism is 60^@ and the minimum deviation is 30^@ , then the angle of incidence is

The refracting angle of a prism is A, and refractive index of the material of the prism is cot (A/2) . The angle of minimum deviation is

The refracting angle of the prism is 60^@ and the refractive index of the material of the prism is sqrt(3) . Calculate the angle of minimum deviation in degree.