`(-2)^(-5)xx(-2)^6`

((3)^(-5)xx5^(-2)xx27^(2/3))/(6^2xx25^(1/2)xx49^(-1/2))

(-5)^(2)xx(-5)^(-3)=(-5)^(-6)

Find the value of (-2)^-5 times (-2)^6 is (a) 2 (b) -2 (c) -5 (d) 6

Find x: (2/5)^(2x+6)xx(2/5)^3=(2/5)^(x+2)

Simplify: ((5^(-3)xx7^(4))/(7^(-2)xx5^(-6)))^((5)/(2))xx((5^(-3)xx7^(-3))/(7^(5)xx5^(2)))^((3)/(2))

Simplify: ((5^(-3)xx7^(4))/(7^(-2)xx5^(-6)))^((5)/(2))xx((5^(-3)xx7^(-3))/(7^(5)xx5^(2)))^((3)/(2))

Using appropriate properties find.(i) -(2)/(5)xx(3)/(5)+(5)/(2)-(3)/(5)xx(1)/(6)( ii) (2)/(5)xx(-(3)/(7))^(2)-(1)/(6)xx(3)/(2)+(1)/(14)xx(2)/(5)

Find the value of n, where n is an integer and 2^(n-5)xx6^(2n-4)=1/(12^(4)xx2)

Let S_(n) denote the sum of n terms of the series 1^(2)+3xx2^(2)+3^(2)+3xx4^(2)+5^(2)+3xx6^(2)+7^(2)+ . . . . Statement -1: If n is odd, then S_(n)=(n(n+1)(4n-1))/(6) Statement -2: If n is even, then S_(n)=(n(n+1)(4n+5))/(6)