`pi/4 + pi - pi/3 - pi/6`

(pi)/(4)-pi/3-pi/6

sin pi/3 = 2sin pi/6 cos pi/6

sin^(-1)((-1)/2) (a) pi/3 (b) -pi/3 (c) pi/6 (d) -pi/6

If |veca.vecb|=sqrt(3)|vecaxxvecb| then the angle between veca and vecb is (A) pi/6 (B) pi/4 (C) pi/3 (D) pi/2

If tanA=1/2andtanB=1/3, then: A+B= (a) pi/4 (b) 0 (c) pi (d) pi/6

The angle of intersection of the curves y=2\ s in^2x and y=cos2\ x at x=pi/6 is pi//4 (b) pi//2 (c) pi//3 (d) pi//6

If A={0 , pi/6, pi/4, pi/3, pi/2} and f: A rarr B is a surjection defined by fx) = cosx then find B

The solution o the equation cos^(2)theta+s int h eta+1=0 lies in the interval (-pi/4,pi/4) b.(pi/4,3 pi/4)c(3 pi/4,5 pi/4)d.(5 pi/4,7 pi/4)

A solution of the equation cos^(2)theta+s int h eta+1=0 lies in the interval (-pi/4,pi/4) b.(pi/4,3 pi/4)c(3 pi/4,5 pi/4)d*(5 pi/4,7 pi/4)

The period of cos(theta/2) is (A) 2 pi (B) 4 pi (C) pi (D) 6 pi