`(2x)/3 - (3x)/4 + (5x)/2 - 9/4 = 0`

(5-2x) (3x + 4) (x-4)> = 0

x^2-2x+2=0"( 2)"x^2-3x+3=0x^2-3x+4=0"( 4)"x^2-5x+5=0 A quadratic equation whose roots are cosec20 andsec 0 can be(1) x2-2x+ 2 =0(2) x2-3x + 3 = 0(3) x2-3x+ 4= 0(4) x-5x+5= 0

Given that (5x - 3)^3 + (2x + 5)^3 + 27(4- 3x)^3 = 9(3 - 5x)(2x + 5)(3x - 4) , then the value of (2x + 1) is:

{:(3x - 2y = 4),(5x - 2y = 0):}

Solve the following equations and also check your result in each case: (i) ((3x+1))/(16)+((2x-3))/7=((x+3))/8+((3x-1))/(14) (ii) ((1-2x))/7-((2-3x))/8=3/2+x/4 (iii) (9x+7)/2-\ (x-(x-2)/7)=36 (iv) 0. 18\ (5x-4)=\ 0. 5 x+0. 8

Evaluate lim_(x to sqrt(3)) (3x^(8) + x^(7) - 11x^(6) - 2x^(5) 9x^(4) - x^(3) + 35x^(2) + 6x + 30)/(x^(5) - 2x^(4) + 4x^(2) - 9x + 6)