`lim_(x->0) (1-cos x)/(sin^2 x)`

lim_(x rarr0)(1-cos x)/(sin x)

find the value lim_(x rarr0)(1-cos x)/(sin^(2)x)

lim_(x rarr0)(1-cos2mx)/(sin^(2)n)x

The value of lim_(xto0) ((1-cos2x)sin5x)/(x^(2)sin3x) is

For a in R^(+) such that lim_(x rarr0)(1-cos ax)/(x^(2))=lim_(x rarr pi)(sin x)/(pi-x) then a=

For a in R^(+) such that lim_(x rarr0)(1-cos ax)/(x^(2))=lim_(x rarr pi)(sin x)/(pi-x) then the value of a is

Statement-1 : lim_(x to 0) (1 - cos x)/(x(2^(x) - 1)) = (1)/(2) log_(2) e . Statement : lim_(x to 0) ("sin" x)/(x) = 1 , lim_(x to 0) (a^(x) - 1)/(x) = log a, a gt 0

lim_ (x rarr0) (1-cos4x) / ((sin3x) ^ (2))