Home
Class 9
MATHS
In figure, bar(AB) is a diameter of the ...

In figure, `bar(AB)` is a diameter of the circle, `bar(CD)` is a chord equal to the radius of the circle. `bar(AC)` and `bar(BD)` when extended intersect at a point E. Prove that `angle AEB = 6^@`.

Text Solution

Verified by Experts

The correct Answer is:
`angleAEB=60^(@)`
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

Find the value of angle ‘x’ in the figure. bar(AB)||bar(CD)

Name the following parts from the given figure where 'O' is a centre of the circle. bar AO ,

In rectangleABCD if bar(AB) |\| bar(CD) then angleA and angleD are

Name the following parts from the adjacent figure where 'O' is the centre of the circle. bar(AB)

In the given figure, AB is the diameter of the circle centered at O. If angle COA = 60^(@) , AB = 2r , AC = d . and CD = l, then l is equal to

Name the following parts from the adjacent figure where 'O' is the centre of the circle. bar(AO)

Name the following parts from the adjacent figure where 'O' is the centre of circle. bar(AC)

In the given figure ‘O’ is the centre of the circle and AB, CD are equal chords. If angleAOB = 70^@ . Find the angles of the Delta OCD

Name the following parts from the adjacent figure where 'O' is the centre of circle. bar(ACB)

In the figure, O is the centre of the circle and AB = CD. OM is perpendicular on bar(AB) and bar(ON) is perpendicular on bar(CD) . Then prove that OM = ON.