4.Find the value of "1/(sqrt5+sqrt2)

Find the value of 6/(sqrt(5)-\ sqrt(3)) , it being given that sqrt(3)=1. 732\ \ a n d\ \ sqrt(5)=2. 236

Find the value of 5/(sqrt11-sqrt7)

If sqrt(2)=1*4 and sqrt(3)=1*7 , find the value of 1/(sqrt(3)-sqrt(2)) , correct to one place of decimal.

if sqrt2=1.414and sqrt3=1.732 then find the value of 4/(3sqrt3-2sqrt2)+3/(3sqrt3+2sqrt2)

Rationalize the denominator and simplify to find the value of 4/(sqrt(5)+sqrt(3)) , given that sqrt(5)=2.236 and sqrt(3)=1.732

Rationalize the denominatior and simplify to find the value of (4)/(sqrt(5) + sqrt(3)) (Given : sqrt(5) = 2.236 and sqrt(3) = 1.732)

Find the value of: 1/(1+sqrt2)+1/(sqrt2+sqrt3)+1/(sqrt3+sqrt4)+...1/(sqrt99+sqrt100)

If sqrt(2)=1.414 , then find the value of (1)/(2+sqrt(2))

Using binomial theorem, expand {(x+y)^5+(x-y)^5}dot and hence find the value of {(sqrt(2)+1)^5+(sqrt(2)-1)^5}dot

Find the value of sqrt((x+2sqrt((x-1)))]+sqrt((x-2sqrt((x-1)))] =