In the measurement of a physical quantity `x` `=(A sqrt(B))/(C^(2))`.The percentage error in measurement of the quantities `A,B,C` are `1%,2%` and `2%` respectively.Then the maximum possible percentage error in `x` is `%`.

In the measurement of a physical quantity X = (A^(2) B)/(C^(1//3) D^(3)) . The percentage erros introduced in the measurments of the quantities A,B,C and D are 2%,2%,4% and 5% respectively. Then the minimum amount of percentage of error in the meaurement fo X is contributed by

In the measurement of a physical quantity X = (A^(2)B)/(C^(1//3)D^(3)) . The percentage errors introduced in the measurement of the quantites A,B,C and D are 1%, 3% , 4% and 5% respectively . Then the minimum amount of percenatage of error in the measurment of X is contributed by

A physical quantity is given by X=M^(a)L^(b)T^(c) . The percentage error in measurement of M,L and T are alpha, beta and gamma respectively. Then maximum percentage error in the quantity X is

A physical quantity A is dependent on other four physical quantities p,q,r and s as given by A=(sqrt(pq))/(r^(2)s^(3)) . The percentage error of measurement in p,q,r and s are 1%,3%,0.5% and 0.33% respectively, then the maximum percentage error in A is

A Physical quantity P is given by P= (A^2sqrtB)/C , and the percentage errors in the measurements of A, B and C are 1% , 2 % and 4% respectively. Find the percentage error in P.

The percentage error in measurements of length and time period is 2% and 1% respectively . The percentage error in measurements of 'g' is

A physical quantity Y is expressed as Y= (p^2)/(r )((q)/(sqrt(s)))^3 If the percentage error in the measurement of p,q,r and s are 4%, 2%, 1% and 3% respectively, caluclate the percentage error in Y.

A physical quantity X is given by X=(2k^(3)l^(2))/(msqrt(n)) The percentage error in the measurement of K,l,m and n are 1%,2%, 3% and 4% respectively. The value of X is uncertain by

.A physical quantity P=A^(3)B^(2)/CD ,If the percentage errors in the measurement of A,B,C and Dare 1%,2%,3% and 4% then what is the maximum error in the measurement of P

The heat dissipated in a resistance can be obtained by the measurement of resistance, current and time. If the maximum precentage error in the mesurement of these quanties is %,2% and 1% respectively. The maximum percentage error in the determination of the dissipated heat is -