`(4x+5)/(4x) = (4x)/(4x) + 5/(4x) = 1+5/(4x)`

(4x+5)/(4x)=5

(2x + 1) / (x) + (4x) / (2x + 1) = 5

Use the identity (x+a)(x+b)=x^2+(a+b)x+ab to find the following products. (i) (x+3)(x+7) (ii) (4x+5)(4x+1) (iii) (4x+5)(4x+1) (iv) (4x+5)(4x-1) (v) (2x+5y)(2x+3y) (vi) (2a^2+9)(2a^2+5) (vii) (xyz-4)(xyz-2)

If f (x) =(x+3)/(4x-5) and t =(3+ 5x)/( 4x -1), then f (t) is

Solve : (5x)/(4)-1 le (4x-1)/(3)

((x+1)(4x-3)-4x^(2)+5)/(4x+1)=2

(4x-3)/5-(5x-3)/8=1

x ^ (2) -4x-5 = (x-5) (x + 1)

If (4x+8)/(5x+8) = 5/6 , then x = ?