If `f(x) = 1/x , g(x) = sqrtx ` find ` gof(x)?`

If f(x) = 1//x, g(x) = sqrt(x) for all x in (0,oo) , then find (gof)(x).

If f(x) =(4-x)^2 and g(x) =sqrtx , then (g o f) (x)=

If f:R -> R, g:R -> R defined as f(x) = sin x and g(x) = x^2 , then find the value of (gof)(x) and (fog)(x) and also prove that gof != fog .

If f(x) = sqrtx , g(x) = root(3)(x+1) , and h(x) = root(4)(x+2), " then "f(g(h(2)))=

Let f (x) = [x] and g (x ) =|x| , AA x in R then value of gof (( - 5 ) /(3)) + fog (( - 5)/(3)) is equal to: ( where f _ 0 g (x) = f (g (x))) .

Let f(x)=2x-sinx and g(x) = 3^(sqrtx) . Then

If (x -1)/( sqrtx +1) = 4 + (sqrtx - 1 )/(2) find x

Let f : R rarr R be defined by f(x) = x^(2) + 3x + 1 and g : R rarr R is defined by g(x) = 2x - 3, Find, (i) fog (ii) gof

Let R^+ be the set of all non-negative real numbers. If f: R^+\ ->R^+ and g: R^+\ ->R^+ are defined as f(x)=x^2 and g(x)=+sqrt(x) . Find fog and gof . Are they equal functions.