In the reaction,
`2H_2(g)+O_2(g) rarr 2H_2O(l)`
The stoichiometry tells that hydrogen and oxygen react to produce water in the mass ratio of

Options

A. `4:16`
B. `4:32`
C. `2:1`
D. `4:2`

Answer

To find the mass ratio of hydrogen to oxygen in the reaction \(2H_2(g) + O_2(g) \rightarrow 2H_2O(l)\), we will follow these steps:

### Step 1: Identify the moles of reactants
From the balanced equation, we see that:
- 2 moles of \(H_2\) react with 1 mole of \(O_2\).

### Step 2: Calculate the mass of hydrogen
The molar mass of hydrogen (\(H\)) is approximately 1 g/mol. Therefore, for 2 moles of \(H_2\):
\[ \text{Mass of } H_2 = 2 \text{ moles} \times 2 \text{ g/mol} = 4 \text{ grams} \]

### Step 3: Calculate the mass of oxygen
The molar mass of oxygen (\(O\)) is approximately 16 g/mol. Therefore, for 1 mole of \(O_2\):
\[ \text{Mass of } O_2 = 1 \text{ mole} \times 32 \text{ g/mol} = 32 \text{ grams} \]

### Step 4: Determine the mass ratio of hydrogen to oxygen
Now, we can find the mass ratio of hydrogen to oxygen:
\[ \text{Mass ratio of } H_2 : O_2 = 4 \text{ grams} : 32 \text{ grams} \]

### Step 5: Simplify the mass ratio
To simplify the ratio:
\[ \frac{4}{32} = \frac{1}{8} \]
Thus, the mass ratio of hydrogen to oxygen is \(1:8\).

### Final Answer
The mass ratio of hydrogen to oxygen in the reaction is \(1:8\).

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