Bond angle is minimum for which of the following ?

Options

A. `H_2Se`
B. `H_2T_e`
C. `H_2O`
D. `H_2S`

Answer

To determine which compound has the minimum bond angle among the given options, we need to analyze the bond angles of hydrides of group 16 elements (O, S, Se, Te).

### Step-by-Step Solution:

1. **Identify the Group 16 Hydrides**: The hydrides of group 16 elements include:
- Water (H2O)
- Hydrogen sulfide (H2S)
- Hydrogen selenide (H2Se)
- Hydrogen telluride (H2Te)

2. **Understand the Bond Angles**:
- **Water (H2O)**: The bond angle is approximately 104.5° due to the presence of two lone pairs on the oxygen atom, which exert repulsion on the hydrogen atoms, pushing them closer together.
- **Hydrogen Sulfide (H2S)**: The bond angle is approximately 92° because the larger size of sulfur compared to oxygen reduces the lone pair repulsion.
- **Hydrogen Selenide (H2Se)**: The bond angle is slightly larger than that of H2S, around 91°.
- **Hydrogen Telluride (H2Te)**: The bond angle is even smaller, around 90°.

3. **Compare the Bond Angles**:
- H2O: 104.5°
- H2S: 92°
- H2Se: ~91°
- H2Te: ~90°

4. **Conclusion**: The bond angle decreases as we move down the group from oxygen to tellurium due to the increasing size of the central atom and the corresponding decrease in lone pair repulsion. Therefore, the minimum bond angle is found in hydrogen telluride (H2Te), which is approximately 90°.

### Final Answer:
The bond angle is minimum for **Hydrogen Telluride (H2Te)**.