The products formed by reaction between `H_2S` and Fluorine are

Options

A. `SF_2` and HF
B. `SF_4` and HF
C. `SF_6` and HF
D. `SF_6,S` and HF

Answer

To determine the products formed by the reaction between hydrogen sulfide (H₂S) and fluorine (F₂), we can follow these steps:

### Step 1: Write the Reactants
The reactants in this reaction are hydrogen sulfide (H₂S) and fluorine (F₂).

### Step 2: Identify the Reaction
When H₂S reacts with F₂, it undergoes a halogenation reaction where fluorine replaces the hydrogen atoms in H₂S.

### Step 3: Write the Balanced Chemical Equation
The reaction can be represented as follows:

\[ \text{H}_2\text{S} + 6\text{F}_2 \rightarrow \text{SF}_6 + 6\text{HF} \]

### Step 4: Identify the Products
From the balanced equation, we can see that the products formed are:
1. Sulfur hexafluoride (SF₆)
2. Hydrogen fluoride (HF)

### Step 5: Verify the Balancing
To ensure the equation is balanced:
- On the left side, we have 2 hydrogen (H) from H₂S and 12 fluorine (F) from 6 F₂.
- On the right side, we have 1 sulfur (S) in SF₆, 6 hydrogen (H) in 6 HF, and 6 fluorine (F) in SF₆ plus 6 in HF, totaling 12 fluorine.

Thus, the equation is balanced.

### Final Answer
The products formed by the reaction between H₂S and fluorine are sulfur hexafluoride (SF₆) and hydrogen fluoride (HF).

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