An element is in `M^(3+)` from , its electronic configuration is `[Ar]3d^1`,the ion is

Options

A. `Ca^(2+)`
B. `Sc^(+3)`
C. `Ti^(3+)`
D. `Ti^(4+)`

Answer

To determine the identity of the element with the electronic configuration `[Ar] 3d^1` in its `M^(3+)` form, we can follow these steps:

### Step 1: Understand the Electronic Configuration
The given electronic configuration is `[Ar] 3d^1`. This indicates that the element has the same electron configuration as Argon (which has an atomic number of 18) plus one electron in the 3d subshell.

### Step 2: Determine the Total Number of Electrons
Since the ion is in the `M^(3+)` state, it means that the element has lost 3 electrons. To find the total number of electrons in the neutral atom, we need to add 3 to the number of electrons in the ion.

- The configuration `[Ar] 3d^1` corresponds to 18 (from Argon) + 1 (from 3d) = 19 electrons in the neutral atom.

### Step 3: Identify the Element
The atomic number of the element is 19, which corresponds to Potassium (K). However, we need to check if Potassium can exist in a `3+` oxidation state.

- The atomic number of Scandium (Sc) is 21, and its neutral configuration is `[Ar] 4s^2 3d^1`. When Scandium loses 3 electrons to form `Sc^(3+)`, it loses both 4s electrons and the single 3d electron, resulting in the configuration `[Ar]`, which is not what we have.

- The atomic number of Titanium (Ti) is 22, with a neutral configuration of `[Ar] 4s^2 3d^2`. When Titanium loses 3 electrons to form `Ti^(3+)`, it loses both 4s electrons and one 3d electron, resulting in the configuration `[Ar] 3d^1`, which matches our given configuration.

### Step 4: Conclusion
Thus, the element that corresponds to the `M^(3+)` ion with the electronic configuration `[Ar] 3d^1` is Titanium (Ti).

**Final Answer: Titanium (Ti)**

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