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The slopes between pV versus V and pV ve...

The slopes between pV versus V and pV versus p at constant temperature ae respectively

A

zero and 1

B

1 and zero

C

zero and zero

D

1/2 and 1

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the slopes between \( PV \) versus \( V \) and \( PV \) versus \( P \) at constant temperature, we can follow these steps: ### Step 1: Understand the Ideal Gas Law The ideal gas law is given by the equation: \[ PV = nRT \] where: - \( P \) = pressure - \( V \) = volume - \( n \) = number of moles of gas - \( R \) = universal gas constant - \( T \) = temperature At constant temperature, \( nRT \) is a constant. ### Step 2: Analyze the First Slope (PV vs. V) To find the slope of the graph of \( PV \) versus \( V \): - Since \( PV = nRT \) is constant, we can express this as: \[ PV = C \quad (where \, C = nRT) \] - Rearranging gives: \[ P = \frac{C}{V} \] This indicates that as \( V \) increases, \( P \) decreases, and the relationship is hyperbolic. However, if we consider \( PV \) as a function of \( V \): - The value of \( PV \) remains constant regardless of changes in \( V \). - Therefore, when plotting \( PV \) against \( V \), the graph will be a horizontal line, indicating that the slope is 0. ### Step 3: Analyze the Second Slope (PV vs. P) Now, we find the slope of the graph of \( PV \) versus \( P \): - From the ideal gas equation, we can express \( V \) as: \[ V = \frac{C}{P} \] - This shows that as \( P \) increases, \( V \) decreases, again indicating a hyperbolic relationship. However, if we consider \( PV \) as a function of \( P \): - The value of \( PV \) remains constant regardless of changes in \( P \). - Therefore, when plotting \( PV \) against \( P \), the graph will also be a horizontal line, indicating that the slope is again 0. ### Conclusion Thus, the slopes between \( PV \) versus \( V \) and \( PV \) versus \( P \) at constant temperature are both 0. Therefore, the answer is: \[ \text{0 and 0} \] ### Final Answer The correct option is **0 and 0**. ---
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