Critical temperature of gases are given as SO2 (630 K),CH4 (190 K), H2 (33k). Which of the following is the correct order of extent of adsorption?

Options

A. `SO_2 gt CH_4gtH_2`
B. `H_2ltCH_4 gtSO_2`
C. `H_2 gtCH_4gtSo_2`
D. `H_2=CH_4gtSO_2`

Answer

To determine the correct order of extent of adsorption for the given gases based on their critical temperatures, we can follow these steps:

### Step 1: Understand Critical Temperature
Critical temperature is defined as the temperature above which a gas cannot be liquefied, regardless of the pressure applied. It indicates the strength of intermolecular forces in the gas.

### Step 2: Analyze the Given Critical Temperatures
The critical temperatures provided for the gases are:
- SO2: 630 K
- CH4: 190 K
- H2: 33 K

### Step 3: Relate Critical Temperature to Adsorption
The extent of adsorption is influenced by the critical temperature:
- A higher critical temperature indicates stronger intermolecular forces (like Van der Waals forces).
- Stronger intermolecular forces lead to greater ease of liquefaction and thus a higher extent of adsorption.

### Step 4: Compare the Critical Temperatures
From the given values:
- SO2 has the highest critical temperature (630 K).
- CH4 has a moderate critical temperature (190 K).
- H2 has the lowest critical temperature (33 K).

### Step 5: Establish the Order of Adsorption
Based on the relationship between critical temperature and adsorption:
- Since SO2 has the highest critical temperature, it will have the highest extent of adsorption.
- CH4, with a lower critical temperature than SO2 but higher than H2, will have a moderate extent of adsorption.
- H2, with the lowest critical temperature, will have the lowest extent of adsorption.

Thus, the order of extent of adsorption is:
**SO2 > CH4 > H2**

### Conclusion
The correct order of extent of adsorption based on the given critical temperatures is:
**SO2 > CH4 > H2**

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