Home
Class 12
CHEMISTRY
Foe the rate law, =K[A]^(3//2)[B]^(-1) t...

Foe the rate law, =`K[A]^(3//2)[B]^(-1)` the overall order of a reaction is

A

zero

B

half

C

one

D

two

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

For a reaction whose rate expression is rate (dx)/(dt)=k[A]^(1//2) [B]^(3//2) the overall order of the reaction will be:

If the rate expression for a reaction is dx/dt=k[A]^(1/2)[B]^(3/2) ,the overall order of the reaction is: (a) 2 (b) 3 (c) 4 (d) 5

If the rate expression for a reaction is dx/dt=k[A]^(1/2)[B]^(3/2) ,the overall order of the reaction is: (a) 2 (b) 3 (c) 4 (d) 5

If the rate expression for a reaction is (dx)/(dt)=k[A]^(1//2)[B]^(2//3) , the overall order of the reaction is :

The reaction A+B+Crarr products is found to obey the rate law, r=(d[A])/(dt)=K[A]^(2)[B]^((3)/(2))[C]^(-(1)/(2)) . The overall order of the reaction is

The rate of reaction , A + B+C to product is given by : rate =K [A] ^(1//2) [B] ^(1//3) [C ] . The order of the reaction is _______.