Ionic bonds will be formed more esaily between elements with comparratively

Options

A. low ionisation enthalpy and high electron affinity
B. high ionisation enthalpy and high electron affinity
C. low ionisation enthalpy and low electron affinity
D. high ionisation enthalpy and low electron affinity

Answer

To determine which elements will form ionic bonds more easily, we need to analyze the characteristics of the elements involved in the bond formation. Here’s a step-by-step solution:

### Step 1: Understand Ionic Bond Formation
Ionic bonds are formed when one atom donates an electron to another atom, resulting in the formation of charged ions: cations (positive) and anions (negative).

### Step 2: Identify Key Properties
The two key properties that affect ionic bond formation are:
- **Ionization Enthalpy (IE)**: The energy required to remove an electron from an atom in the gaseous state.
- **Electron Gain Enthalpy (EGE)**: The energy released when an electron is added to an atom in the gaseous state.

### Step 3: Analyze the Requirements for Ionic Bonding
For ionic bonding to occur easily:
- The atom that loses an electron (usually a metal) should have a **low ionization enthalpy**. This means it can lose an electron easily.
- The atom that gains an electron (usually a non-metal) should have a **high electron gain enthalpy**. This means it has a strong tendency to accept an electron.

### Step 4: Evaluate the Options
Now we will evaluate the provided options based on the above analysis:
1. **Low ionization enthalpy and high electron affinity**: This is favorable for ionic bond formation.
2. **High ionization enthalpy and high electron affinity**: This is not favorable because the metal cannot easily lose an electron.
3. **Low ionization enthalpy and low electron affinity**: This is not favorable because the non-metal does not have a strong tendency to gain an electron.
4. **High ionization enthalpy and low electron affinity**: This is the least favorable scenario for ionic bond formation.

### Step 5: Conclusion
The most favorable condition for the formation of ionic bonds is when there is **low ionization enthalpy** and **high electron affinity**. Therefore, the correct answer is:

**Low ionization enthalpy and high electron affinity.**

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