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The decreasing order of the repulsive in...

The decreasing order of the repulsive interaction of electron pair is (here,lp=lone pair,bp=bond pair)

A

`lp-lpgtlp-bpgtbp-bp`

B

`lp-bpgtlp-lpgtbp-bp`

C

`lp-lpgtbp-bpgtlp-bp`

D

`bp-bpgtlp-lpgtlp-bp`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the decreasing order of repulsive interactions of electron pairs, we need to analyze the interactions between different types of electron pairs: lone pairs (lp) and bond pairs (bp). ### Step-by-Step Solution: 1. **Understanding Electron Pairs**: - Electron pairs can be classified into two types: lone pairs (lp) and bond pairs (bp). - Lone pairs are non-bonding pairs of electrons localized on a single atom. - Bond pairs are shared between two atoms in a covalent bond. 2. **Nature of Repulsion**: - Lone pairs are attracted to the nucleus of only one atom, while bond pairs are attracted to the nuclei of two atoms. - This difference in attraction leads to varying degrees of repulsion between the electron pairs. 3. **Comparing Repulsions**: - Lone pair-lone pair (lp-lp) interactions are the strongest because both lone pairs are repelling each other without any additional attraction from another nucleus. - Lone pair-bond pair (lp-bp) interactions are weaker than lp-lp interactions because the bond pair is also attracted to another nucleus, reducing the repulsive effect. - Bond pair-bond pair (bp-bp) interactions are the weakest since they are shared between two atoms, leading to a balanced attraction that minimizes repulsion. 4. **Establishing the Order**: - Based on the above analysis, we can establish the order of repulsion: - **lp-lp > lp-bp > bp-bp** 5. **Conclusion**: - Therefore, the decreasing order of repulsive interactions of electron pairs is: - **lp-lp > lp-bp > bp-bp** ### Final Answer: The correct decreasing order of the repulsive interaction of electron pairs is: **lp-lp > lp-bp > bp-bp**
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