The electonegativities of elements A and B are 1.2 and 3.4 units respectively the type of bond connecting A and B in compound AB is

Options

A. covalent
B. ionic
C. coordinate covalent
D. polar covalent

Answer

To determine the type of bond connecting elements A and B in compound AB, we will follow these steps:

### Step 1: Identify the electronegativities of elements A and B.
- Given: Electronegativity of element A = 1.2 units
- Given: Electronegativity of element B = 3.4 units

### Step 2: Calculate the difference in electronegativity between A and B.
- Electronegativity difference (ΔEN) = Electronegativity of B - Electronegativity of A
- ΔEN = 3.4 - 1.2 = 2.2 units

### Step 3: Determine the type of bond based on the electronegativity difference.
- A general rule of thumb states:
- If the electronegativity difference (ΔEN) is greater than 1.7, the bond is primarily ionic.
- If ΔEN is less than 1.7, the bond is primarily covalent.

### Step 4: Analyze the calculated ΔEN.
- Since ΔEN = 2.2, which is greater than 1.7, we conclude that the bond between A and B is ionic.

### Conclusion:
- The type of bond connecting elements A and B in compound AB is an **ionic bond**.

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