Electonegativity and electron affinity of an element A are X and Y respectively hence ionisation potential of A is

Options

A. `X+Y/2`
B. 2X-Y
C. 2Y-X
D. 2X+Y

Answer

To find the ionization potential of element A given its electronegativity (X) and electron affinity (Y), we can use the relationship derived from the molecular scale. Here’s the step-by-step solution:

### Step 1: Understand the Definitions
- **Electronegativity (X)**: A measure of the tendency of an atom to attract a bonding pair of electrons.
- **Electron Affinity (Y)**: The amount of energy released when an electron is added to a neutral atom to form a negative ion.
- **Ionization Potential (IP)**: The energy required to remove an electron from an atom in its gaseous state.

### Step 2: Use the Relationship
According to the molecular scale, the relationship between electronegativity, electron affinity, and ionization potential can be expressed as:
\[ X = \frac{IP + Y}{2K} \]
Where K is a constant.

### Step 3: Rearranging the Equation
To find the ionization potential (IP), we rearrange the equation:
\[ IP = 2K \cdot X - Y \]

### Step 4: Simplifying the Equation
Assuming K is a constant that can be simplified or set to 1 for this context, we can express the ionization potential as:
\[ IP = 2X - Y \]

### Conclusion
Thus, the ionization potential of element A can be expressed as:
\[ IP = 2X - Y \]

### Final Answer
The ionization potential of A is \( 2X - Y \).

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