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Choose the incorrect statement out of th...

Choose the incorrect statement out of the following .

A

LiCl and `MgCl_2` are soluble in ethanol

B

LiCl and `MgCl_2` are deliquescent and crystallised from aqueous solution as hydrates

C

`Li_2O` and MgO combines with excess oxygen to produce superoxide

D

carbonates of Li and Mg decomposes easily on heating to from oxides and `CO_2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question of identifying the incorrect statement regarding Lithium (Li) and Magnesium (Mg), we will analyze each statement provided in the options. ### Step-by-Step Solution: 1. **Understand the Diagonal Relationship**: - Lithium and Magnesium exhibit a diagonal relationship in the periodic table, meaning they share some similar properties due to their similar size and charge density. 2. **Evaluate Each Statement**: - **Option 1**: "LiCl and MgCl2 are soluble in ethanol." - **Analysis**: Both LiCl and MgCl2 are indeed soluble in ethanol. This statement is **correct**. - **Option 2**: "LiCl and MgCl2 are deliquescent and crystallize in the form of hydrates." - **Analysis**: LiCl is known to be deliquescent and can crystallize as LiCl·2H2O, while MgCl2 can crystallize as MgCl2·8H2O. This statement is **correct**. - **Option 3**: "Li2O and MgO combine with excess oxygen to produce superoxide." - **Analysis**: Superoxides are stable with larger cations. Lithium oxide (Li2O) and Magnesium oxide (MgO) do not form superoxides when combined with excess oxygen. This statement is **incorrect**. - **Option 4**: "Carbonates of Lithium and Magnesium decompose easily on heating to form oxides and CO2." - **Analysis**: Lithium carbonate (Li2CO3) and Magnesium carbonate (MgCO3) decompose upon heating to produce their respective oxides and carbon dioxide. This statement is **correct**. 3. **Conclusion**: - After evaluating all the statements, the incorrect statement is **Option 3**: "Li2O and MgO combine with excess oxygen to produce superoxide." ### Final Answer: The incorrect statement is **Option 3**.
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