Complete the following equation
`NH_4Cl (aq) +…I… rarr …II…+2H_2O (l) + NaCl (aq)`
Here, I and II are

Options

A. `NaNO_3`(aq)-I, `N_2` (g)-II
B. `NaNO_2`(aq)-I, `H_2` (g)-II
C. `NaNO_2`(aq)-I, `N_2` (g)-II
D. None of the above

Answer

To complete the equation given in the question, we start with the reactants and products specified:

**Given Equation:**
\[ \text{NH}_4\text{Cl (aq)} + \ldots \text{I} \rightarrow \ldots \text{II} + 2\text{H}_2\text{O (l)} + \text{NaCl (aq)} \]

### Step 1: Identify the Reactants and Products
We know that NH4Cl (ammonium chloride) is reacting with another compound that we need to identify. The products include water (H2O) and sodium chloride (NaCl).

### Step 2: Analyze the Reaction
Ammonium chloride (NH4Cl) can react with sodium nitrite (NaNO2) in an acid-base reaction. In this case, we need to find a suitable compound that can provide the necessary nitrogen and oxygen atoms.

### Step 3: Determine the Missing Compounds
1. **I**: The first compound (I) that reacts with NH4Cl should be NaNO2 (sodium nitrite).
2. **II**: The second compound (II) that is produced in the reaction is nitrogen gas (N2).

### Step 4: Write the Complete Reaction
The complete balanced equation will be:
\[ \text{NH}_4\text{Cl (aq)} + \text{NaNO}_2 \rightarrow \text{N}_2 (g) + 2\text{H}_2\text{O (l)} + \text{NaCl (aq)} \]

### Final Answer:
- **I** = NaNO2 (sodium nitrite)
- **II** = N2 (nitrogen gas)